Question

A solution has been prepared by dissolving 10g of urea in 80g of water. what is the mass percent of urea in solvent.
... answer fast plz​

Answer 1

Answer:

11.11 %

Explanation:

mass of urea = 10 g = $M_{urea}$ .

mass of water = 80 g = $M_{water}$ .

mass % of urea in the solution = $\frac{M_{urea}}{M_{urea}+M_{water}} *100$

                                                   = $\frac{10}{90} * 100$ = 11.11%.

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