Question

a solution having 20% (w/w) of NaOH then find mole fraction of NaOH and mole fraction of H2O​

Answer 1

Explanation:

Let the mass of solution be x gram.

Then mass of NaOH present in it= x*20/100

Molar mass of NaOH= 40gram

So, number of moles of NaOh present in the solution = (20x/100)*1/40 = x/200

Now,mass of solvent present in the solution =mass of solution-mass of solvent = x-20x/100 =80x/100 (in grams)

So molality of solution=(x/200)/(80x/100)*1000 =6.25

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