Chemistry, asked by satakshi4079, 1 year ago

A solution I prepared by adding 2g of a substance A to 18 g of water. Calculate the mass per cent of the solute.

Answers

Answered by ganeshraj44
0

Answer:

so 10%of solute is present in the solution.

Explanation:

the percentage of solute in the solution is=mass of solute *100

total mass

=2/20*100 =10

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
10

\huge\sf\pink{Answer}

☞ Your Answer is 10%

\rule{110}1

\huge\sf\blue{Given}

➳ Mass of solute, A = 2 g

➳ Mass of solvent (water) = 18 g

\rule{110}1

\huge\sf\gray{To \:Find}

✭ Mass % of the Solute?

\rule{110}1

\huge\sf\purple{Steps}

We know,

Mass of solution = Mass of solute + Mass of solvent

➝ 2 g + 18 g

➝ 20 g.

So now,

\sf {Mass\:\%\:of\:A=\dfrac{Mass\:of\:A}{Mass\:of\:solution}\times{}100}

Substituting the given values,

\dashrightarrow\sf{\dfrac{2\:g}{20\:g}\times{}100}\\

\dashrightarrow\sf{\dfrac{100}{10}\%}\\

\orange{\sf{\dashrightarrow{Mass\:\%\:of\:A=}\:\sf{10\%.}}}

\rule{170}3

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