Question

A solution is at 27 degrees Celsius. If the solution was placed in a freezer able to freeze it down to 100 degrees Kelvin, what would be the change in temperature?

Answer 1

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Answer 2

Answer:

The change in the temperature calculated is $-200.15K$.

Explanation:

Data given,

The temperature of the solution  ( initial temperature )= $27\textdegree C$

The temperature of the solution after being placed in a freezer ( final temperature ) = $100K$

The change in the temperature =?

As we know,

• The change in the temperature = final temperature - initial temperature

Firstly, we have to change the degree Celsius to Kelvin.

As we know,

• $1\textdegree C$ = $273.15K$
• $27\textdegree C$ = $(27 + 273.15 )K$ = $300.15K$

Now,

• The temperature change = final temperature - initial temperature
• The temperature change = $(100 - 300.15) K$ = $-200.15K$.