A solution is formed by adding 35g of ammonium nitrate to 250g of water. What is the percent by mass of ammonium nitrate? Answer should be expressed with this format ex. 10.10% *
Answers
Explanation:
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
So the concentration of a solution can be expressed as a percent which is the ratio of solute to solution. Can be expressed in percent of mass (m / m) or volume percent (v / v)
\rm Percent\:by\:Mass=\dfrac{mass\:of\:solute}{mass\:of\:solution}\times 100PercentbyMass=
massofsolution
massofsolute
×100
\rm Percent\:by\:Volume=\dfrac{volume\:of\:solute}{volume\:of\:solution}\times 100PercentbyVolume=
volumeofsolution
volumeofsolute
×100
Solution = Solute + Solvent
The solute is the substance that is dissolved usually in smaller amounts when compared to solvents
A solution that has a lot of solutes per solvent is described as concentrated, while a solution with a small amount of solute is called dilute.
Adding 35 g of ammonium nitrate(NH₄NO₃), to 250 g of water (H₂O)
solute = ammonium nitrate = 35 g
solvent = water = 250 g
Solution = Solute + Solvent
Solution = 35 + 250 = 285 grams
Then the mass percentage of ammonium nitrate
\begin{gathered}\rm Percent\:mass=\dfrac{mass\:of\:ammonium\:nitrate}{mass\:of\:solution}\times 100\\\\Percent\:mass=\dfrac{35\:grams}{285\:grams}\times 100\\\\Percent\:mass=12.28\%\end{gathered}
Given : A solution is formed by adding 35g of ammonium nitrate to 250g of water.
To Find : The percent by mass of ammonium nitrate
Solution:
Mass of ammonium nitrate = 35 g
Mass of Water = 250 g
Total Mass = 35 + 250 = 285 g
percent by mass of ammonium nitrate = (35/ 285) * 100
= (7/57) * 100
= 700/57
≈ 12.281 %
mass of ammonium nitrate is about 12.281 %
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