A solution is made by dissolving 5.3 g of Na2CO3 in 250 ml of solution . Find molarity
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Explanation:
Mass of sodium carbonate is 5.3 g.
Volume of solution is 250 mL.
The following formula is used for the calculation of molarity.
M
o
l
a
r
i
t
y
=
M
a
s
s
o
f
s
o
d
i
u
m
c
a
r
b
o
n
a
t
e
M
o
l
a
r
m
a
s
s
o
f
s
o
d
i
u
m
c
a
r
b
o
n
a
t
e
×
S
o
l
u
t
i
o
n
′
s
V
o
l
u
m
e
(
i
n
L
)
Molar mass of sodium carbonate is 106 g/mol.
The conversion of volume from 250 mL into L is done as:
V
o
l
u
m
e
=
250
m
L
×
1
L
1000
m
L
=
0.25
L
Substitute the values in the above equation.
M
o
l
a
r
i
t
y
=
M
a
s
s
o
f
s
o
d
i
u
m
c
a
r
b
o
n
a
t
e
M
o
l
a
r
m
a
s
s
o
f
s
o
d
i
u
m
c
a
r
b
o
n
a
t
e
×
S
o
l
u
t
i
o
n
′
s
V
o
l
u
m
e
(
i
n
L
)
=
5.3
g
106
g
/
m
o
l
×
0.25
L
=
0.2
m
o
l
L
−
1
=
0.2
M
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