Question

A solution is marked as 15 parsent w/w of h2so4 solution? Calculate the molality mole fraction of the solution if the density of the solution is 1.8 g/m. What will be molality?​

Answer 1

☑ Heya mate! Here is your answer ⤵

▶15% H₂SO₄ solution means 15 g of H₂SO₄ is present in 100 g of Water.

✨No. of moles of H₂SO₄ = 15 g / 98 g/mol = 0.153 mol

✨Weight of solvent = 100g - 15g = 85g = 85 × 10^-3 kg

✨Molality = Moles of solute / Weight of Solvent in kg

= 0.153 / (85 × 10^-3)

= 1.8 m

⏩Molality of given solution is 1.8 m …

✨Volume of solution = Mass of solution / Density

= 100 g / 1.1 g/cm^3

= 90.90 cm^3

= 0.090 Litres

✳Molarity = Moles of solute / Volume of solution in litres

= 0.153 / 0.090

≈ 1.7 M ✔

⏩Molarity of given solution is 1.7 M

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