Question

A solution is obtained by mixing 200 g of 30% and
300 g of 20% solution by weight. What is the percentage
of solute in the final solution?
(a) 50%
(b) 28%
(c) 64%
(d) 24%​

Answer 1

Answer : Option (D) 24%

Solution :

According to the question :

200g of 30% solution contains solute

=> 200×30/100 = 60g

And, 300g of 20% solution contains solute

=> 300×20/100 = 60g

Total solute = 60g + 60g = 120g

Given that : Total Solution = 200+300 = 500g

Let, percentage of solute in final solution be x% :

$500 \times \frac{x}{100} = 120 \\ \\ = > x = \frac{120 \times 100}{500} \\ \\ = > x = 24$

So, 24% solute in the final solution.

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