Question

A solution is obtained by mixing 300 gram of 25% solution and 400 gram of 40% solution by mass. Calculate the mass percentage of resulting solution.​

Answer 1

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Total amount of solute present in the mixture is.

Given By:

$\mathsf {300 \times \frac{25}{100} + 400 \times \frac{40}{100} }$

➠ 75 + 160

➠ 235 Gram

Total amount of solution = 300 + 400

➠ 700 Gram

Therefore, mass percentage (w/w) of the solute.

In the resulting solution,

➠ $\frac{235}{700} \times 100$%

➠ (100 - 33.57) %

➠ 66.43 %

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Answer 2

Answer:

A solution is obtained by the mixing 300 gram of 25% and 400 gram of 40% solution by The Mass. calculate the percentage solute of the resulting solution

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Mass of solution of 300 gm of 25%= 300x25/100= 75 gm mass of solution of 400 gm of 40% = 400x40/100= 160 gm total of above =(160+75)= 235 gm in 700 gm solut. the mass is= 235 gm

in 1 gm solut. the mass is=235/700 gm

in 100 gm solut. the mass is=235x100/700 gm

=33.57 gm or 33.75%