Chemistry, asked by Sushantsawant9404, 10 months ago

a solution is obtained by the mixing 300 gram of 25% and 400 gram of 40% solution by The Mass. calculate the percentage solute of the resulting solution

Answers

Answered by Anonymous
13

QUESTION :


A  solution is obtained by the mixing 300 gram of 25% and 400 gram of 40% solution by The Mass. calculate the percentage solute of the resulting solution


ANSWER :


25% of 300 g

= 25/100 × 300 g

= 1/4 × 300 g

= 75 g


Solute = 75 g


40% of 400 g

= 40/100 × 400 g

= 40 × 4 g

= 160 g


Total solute = 160 g + 75 g = 235 g

Total solution = 400 g + 300 g = 700 g


Percentage = 235 g / 700 g × 100

= > 235 / 7 %

= > 33.57%


The percentage of solute is 33.57%

Answered by Anonymous
4




A solution is obtained by the mixing 300 gram of 25% and 400 gram of 40% solution by The Mass. calculate the percentage solute of the resulting solution



{ \red{\mathfrak{\huge{A}}}}{\underline {\underline{\mathfrak{\huge{nswer}}}}}


Mass of solution of 300 gm of 25%= 300x25/100= 75 gm                                      mass of solution of 400 gm of 40% = 400x40/100= 160 gm                                                                total of above  =(160+75)= 235 gm                                       in 700 gm solut. the mass is= 235 gm
in  1 gm    solut. the mass is=235/700 gm
in 100 gm solut. the mass is=235x100/700 gm
                                         =33.57 gm or 33.75%              


Similar questions