Chemistry, asked by sm4923138, 3 days ago

A solution is perpare by disloving 0.822 g of inti 300* 10 d3 of water

Answers

Answered by siddhijadhav539
3

Answer:

A solution prepared by dissolving 0.822g of it in 300cm3 of water has an osmotic pressure of 149 mm Hg at 298k the mdar mass of the solute is 342gmol-1

Explanation:

osmotic pressure= π=149mmHg

=149mmHg

___________=0.169 atm

760(mmHg/atm)

v=300 cm3 =0.3 dm3

R=0.08205 dm3 atm k-1 mol-1

m2=w2RT

πV

M2=

0.822ginto 0.08205 dm3atmk-1mol-1 into

________________________________

0.196 atm into 0.3dm3

=342g mol-1

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