Question

a solution is prepaired by dissolving 36 g of sodium chloride in 100 g of water . find the concentration of solution​

Answer 1

Answer:

mass of solute-36g

mass of solvent-100g

mass of solution-36+100g

- 136g

concentration-36/136*100

-26.47%

Answer 2

Answer:

Concentration C = 6.2 mol/litre

Explanation:

Mass of solute = m = 36 g

Molar mass of solute = M = 58 g/mol ( approx )

Number of moles of solute = n = m/M

n = 36/58 = 0.620 = 0.6 moles

Volume of solvent ( water ) = V = 100 g or cm3 = 0.1 kg or dm3

Concentration of solution / Molarity = C = n/V

C = 0.62/0.1 = 6.2 mol/litre or mol/dm3