Question

A solution is prepared by adding 2 g of a substance A to 18 g of water. calculate the mass per cent of the solute.​

Answer 1

Answer:

• Mass % of solute (A) = 10%.

Step-by-step explanation :

Given that,

• Mass of solute, A = 2 g.
• Mass of solvent (water) = 18 g.

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We know,

Mass of solution = Mass of solute + Mass of solvent

⇒ 2 g + 18 g

⇒ 20 g.

Also,

$\rm{Mass\:\%\:of\:A=\dfrac{Mass\:of\:A}{Mass\:of\:solution}\times{}100}$

Putting the values, we get,

$\implies\rm{\dfrac{2\:g}{20\:g}\times{}100}$

$\implies\rm{\dfrac{100}{10}\%}$

$\implies\rm{Mass\:\%\:of\:A=}\:\bold{10\%.}$

Answer 2

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$\sf{Mass \:percent \:of \:solute =\frac{ mass \:of \:solute}{mass \:of \:solution}</p><p> ×100}$

$\sf{Mass \:of \:solute =>2\: g}$

$\sf{Mass\: of \:solvent => 18\: g}$

$\sf{Mass\: of\: solution =>20\: g}$

MASS OF SOLUTE+MASS OF SOLVENT=>20

$\sf{∴ Mass \:percent \:of \:solute =>\frac{2}{20} ×100}$

$\sf=>10%$%