Question

a solution is prepared by adding 2 g of substance .A to 18g water. Calculate the mass per cent of the solute​

Answer 1

Answer:

10

Explanation:

Mass of solute A= 2 g

Mass of solvent water= 18 g

Mass percent of solute= (Mass of solute/Mass of solution)

= [2/(2+18)]*100

= (2/20)*100

= 0.1*100

= 10

Therefore, mass percent of solute= 10%

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Answer 2

solution:

$\textsf{mass percent of A =}\frac{\textsf{mass of A}}{\textsf{Mass of solution}} \times 100$

$=\frac{\textsf{2g}}{\textsf{2g of A +18 g of water}} \times 100$

$= \frac{2}{20}×100=10%$

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