Question

a solution is prepared by adding 2 gram of substance A to 18 gram of water calculate the mass percentage of the solute


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Answer 1

Answer:

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Explanation:

$\huge\pink{Question}$

$\small\red{A \: solution \: is \: prepared \: by \: adding \: 2 g \: of \: substance \: A \: to \: 18 g \: of \: water. \: The \: mass \: percent \: of \: the \: solute \: is?}$

$\huge\blue{Answer}$

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Hint: A solution consisting of two components is called a binary solution. The components of a binary solution are called the solute and the solvent. A substance (small amount) that dissolves in a large amount of the solvent to form a solution is called the solute. During the solution formation, the components which are present in large excess are called the solvent. They have the same physicality as the solution. For example in the aqueous solution of NaCl and, AgNO3etc. water is the solvent.

Complete step by step answer:

The concentration of the solution in terms of percentage can be expressed in this way

Mass to mass percentage =mass of solute in gms /mass of solution in gms×100%

In the question, we have to find the mass percentage of the solute. Applying the above formula we can calculate the mass percentage of the solute.

Given,

Mass of solute =2gms

Mass of solution =(mass of the solute +mass of solvent)

=(2+18)gms

=20gms

(Since a solution contains solute and solvent and the mass of the solute and solvent is also given so we have calculated the mass of the solution).

Now, applying the above formula to calculate the mass percent of the solute.

The mass percent of the solute =mass of solute in gms / mass of solution in gms × 100%

=2g20g×100%

=110×100%

=10%

(we have put the given values in the formula and after calculating we have the value of mass percent of the solute which is 10%)

Therefore, the mass percent of the solute is 10%.