Question

A solution is prepared by adding 2g of a substance A to 18g of water .Calculate the amss percent of the solute.​

Answer 1

Explanation:

We know that

$\\ \rm{:}\longrightarrow \boxed{\sf Mass\:percent\:of\:A=\dfrac{Mass\:of\:A}{Mass\:of\:Solution}\times 100}$

$\\ \rm{:}\longrightarrow \dfrac{2g}{2g\:of\:A+18g\:of\:water}\times 100$

$\\ \rm{:}\longrightarrow \dfrac{2g}{20g}\times 100$

$\\ \rm{:}\longrightarrow 10\%$

Answer 2

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$Mass \: percent \: of \: solute \: =  \frac{mass \: of \: solute}{mass \: of \: solution}</p><p></p><p></p><p>$

$Mass \: percent \: of \: solute \: = \frac{2}{20} \times 100 \\ \\ \implies Mass \: percent \: of \: solute \: =10\%$

$Mass \: of \: solute \: = \: 2 g \\ \\ </p><p></p><p>Mass \: of \: solvent \: = \: 18 g \\ \\ </p><p></p><p>Mass \: of \: solution \: = \: 20 g \\ \\ </p><p></p><p></p><p>$