Question

A solution is prepared by adding 2g of a substance A to18g of water. calculate the mass per cent of the solute​

Answer 1

Answer:

10%

Explanation:

Mass % of solute = Mass of solute/ Mass of solution× 100

=2 /( 18 +2)× 100

= 2/20× 100

= 1/10× 100

= 10%

Answer 2

$\huge\sf\underline{\pink{A}\blue{N}\red{S}\purple{W}\orange{E}\green{R}}$

$\sf{Mass \:percent \:of \:solute =\frac{ mass \:of \:solute}{mass \:of \:solution}</p><p> ×100}$

$\sf{Mass \:of \:solute =>2\: g}$

$\sf{Mass\: of \:solvent => 18\: g}$

$\sf{Mass\: of\: solution =>20\: g}$

MASS OF SOLUTE+MASS OF SOLVENT=>20

$\sf{∴ Mass \:percent \:of \:solute =>\frac{2}{20} ×100}$

$\sf=>10%$%