Question

a solution is prepared by adding 40 g of sugar in 100 g of water. Calculate the concentration in terms of mass
by mass percentage of solution​

Answer 1

${\mathfrak{\green{\underline{\underline{Answer:-}}}}}$

$\sf{The\;mass\;by\;mass\;percentage\;of\;solution\;is\:28.571\%.}$

${\mathfrak{\green{\underline{\underline{Explanation:-}}}}}$

$\sf{The\;mass\;by\;mass\;percentage\;of\;solution\;is\;given\;by\;the\;following\;relation,}$

$\sf{Mass\;by\;mass\;percentage\;of\;solution=\dfrac{Mass\;of\;the\;solute}{Mass\;of\;the\;solution}\times 100}$

$\sf{Where\;mass\;of\;solution=mass\;of\;solute+mass\;of\;solvent}$

$\sf{We\;are\;given\;that\;40g\;of\;sugar\;is\;being\;dissolved\;in\;100g\;of\;water.\;Therefore,}$

$\sf{Mass\;of\;solute=40g}$

$\sf{Mass\;of\;solvent=100g}$

$\sf{Mass\;of\;solution=mass\;of\;solute+mass\;of\;solvent}$

$\sf{=40g+100g=140g}$

$\sf{Thus,\;mass\;by\;mass\;percentage\;of\;solution=\dfrac{40}{140} \times 100=28.571\%}$

${\boxed{\boxed{\sf{\red{Hence,\;the\;mass\;by\;mass\;percentage\;of\;solution\;is\:28.571\%.}}}}}$