A solution is prepared by adding 53 g of Na2CO3
(molar mass = 106 g mol-1) in 72 g of water. The mole
fraction of Na2CO3 is
(1) 0.40
(2) 0.11
(3) 0.50
(4) 0.22
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Answer:
The mole fraction of NA2CO3 is
4) 0 .22(answer)
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