A solution is prepared by adding 60 gm of methyl alcohol to 120 gm of water. Calculate the mole fraction of methyl of methyl alcohol in it.
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Answer:
0.219
Explanation:
weight of methyl alcohol = 60gm
Molecular weight of methyl alcohol = 32 gm/mol
Number of moles of methly alcohol = wt./mol wt. = 60/32 = 1.875 = n(A)
weight of water = 120gm
Molecular weight of water = 18 gm/mol
Number of moles of water = wt./mol wt. = 120/18 = 6.667 = n(B)
Mole fraction of methyl alcohol = n(A)
n(A) + n(B)
Mole fraction of methyl alcohol = 1.875
1.875+6.667
Mole fraction of methyl alcohol = 1.875/8.542 = 0.219 or 0.22
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