Question

a solution is prepared by bubbling 1.56 g of hydrochloric acid in water here, the volume of the solution is 26.8 ml calculate the molarity of the solution​

Answer 1

Answer:

The first thing to check here is how much hydrogen chloride, HCl, can you dissolve in water at room temperature. This will help you make sure that all the mass of hydrogen chloride will actually dissolve.

At room temperature, hydrogen chloride has a solubility of about 720 g/L, which means that your 26.8-mL sample will hold as much as

26.8mL⋅720 g HCl1000mL=19.3 g HCl

Now that you know that all the hydrogen achloride will actually dissolve, you can use its molar mass to determine how many moles you have in the 1.56-g sample

1.56g⋅1 mole HCl36.5g=0.04274 moles HCl

Now, molarity is defined as moles of solution, which in your case is hydrogen chloride, divided by liters of solution.

molarity=moles of soluteliters of solution

In your case, the molarity of the resulting solution will be

c=0.04274 moles26.8⋅10−3L=1.5948 M

Rounded to three sig figs, the answer will be

c=1.59 M

Answer 2

Answer:

HCL–1.56g=26.8

Moles of HCL=0.04

Number of moles of HCL

Molarity =———————————————

Volume of solution in liter

0.04

=———

0.0268

=1.59M