Question

A solution is prepared by bubbling 1.56grams of HCl in water. Here,the volume of the solution is 26.8mL. Calculate the molarity of the solution. ​

Answer 1

Answer:

Here, we need to find the HCI, can you dissolve in room temperature

26.8 ml 720 g HCI / 1000 ml = 19.3 g HCI

1.56 g 1 mole HCI/ 36.5 g = 0.04274 moles HCI

MOLARITY= moles of solute/ litres of solution

c= 0.04274 / 26.8 .10 (-3) L = 1.5948 M

ROUNDED TO three figs, the answer will be

c= 1.59 m

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