A solution is prepared by disolving
30g urea (NH₂-CO-NH₂) in 300g of
water. What is the molality of the
solution.
Answers
Answered by
3
Answer:
Moles : mass / molar mass
: 30/60 = 1/2 moles
molality = moles / mass of solvent in kg
= 0.5 / 300
= 1.6 mol /kg
Answered by
1
Answer:
refer to the attachment ☺️✌️
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