Question

A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g mol⁻¹) and 1.8 g of glucose (molar mass = 180 g mol⁻¹) in 100 mL of water at 27ºC. The osmotic pressure of the solution is :
(R = 0.08206 L atm K⁻¹ mol⁻¹)
(A) 8.2 atm (B) 1.64 atm
(C) 4.92 atm (D) 2.46 atm

Answer 1

Answer:

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Explanation:

Since at t=0, charge is maximum (=q0).

Therefore current will be zero.

21Li2=31(21Cq2)

or i=3LCq=3qω

From the expression i=ωq02−q2

We have, 3qω=ωq02−q2

or q=23q0

Since at t=0, charge in maximum or q0 so we can write

q=