Question

A solution is prepared by dissolving 0.63 gram of oxalic acid in 100 cm cube of water find the normality of solution

Answer 1

A solution of oxalic acid is prepared by dissolving 0.63g of acid in 250cm cube of the solution .calculate molarity, molality and normality



Answers


Final Answer : Molarity : 0.02M
Normality : 0.04N 

Steps:
1) Oxalic Acid: C2H2O4.(2H2O )
Molar Mass : 126g
Given Mass of Oxalic acid /solute = 0.63g 
no. of moles of solute = 0.63/126 = 0.5 *10^(-2) 

Volume of solution, V = 250cm^3 = 0.25L 
=> Molarity, M
= no. of moles of solute / Volume of solution 


Hence,Molarity = 0.02M 

2) Since, Basicity / Valency Factor of acid is 2 .(Two ionisable H) 
=> Normality =Molarity * Valency Factor 
= 0.02M * 2 = 0.04N.

3) For Molality, Data is insufficient. 
As We can't get Weight of solvent in solution from required data. 

Answer 2

Answer:

here the answer

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