A solution is prepared by dissolving 1.0g of NaOH in water to get 250ml of solution.Calculate its molalrity.
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Explanation:
Molarity= No of moles of solute / Volume of Solution in litres
No.of moles = Mass of Solute / Molar Mass
= 1 / NaoH ( Na = 23) , ( O=16) , (H=1)
= 1/ 23+16+1 = 1/ 40
Volume = 250/1000 = 0.4
= 1/40 * 0.4
Molarity = 0.1 M
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