a solution is prepared by dissolving 1.2×10³kg of hcl 400 ml solution.calculate the normality
plz give me answer
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Answer:
0.082 × 10³
Explanation:
GIVEN- 1.2 × 10³
= 400 ml
NORMALITY= W × 1000/ Eq × V
HERE - W = WEIGHT, Eq= EQUIVALENT WEIGHT, V= VOLUME
= 1.2×10³ × 1000/ 36.461 × 400
= 0.082 × 10³
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