a solution is prepared by dissolving 10 gram of NaOH in 90 gram of water calculate the mole fraction of water
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Explanation:
According to raoult's law,
p0p0−p=m×Ww×M
Where,
p0 is Vapour pressure of pure water
p is vapour pressure of solvent
w is weight of solute
m is molecular weight of solute
W is molecular weight of solvent
3232−31.84=m×20010×18
⇒m=0.0050.9=180
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