Chemistry, asked by amankoli5500, 1 year ago

A solution is prepared by dissolving 10g of naoh in 100ml of solution . its molarity is

Answers

Answered by kobenhavn
6

Answer: Molarity is 0.25 M

Explanation: Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

Moles=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}}=\frac{10}{40}=0.25moles  

V_s = Volume of solution in ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.25moles\times 1000}{100ml}=2.5mole/L

Therefore, the molarity of solution will be 0.25 mole/L.

Answered by sujithavenkatesan3
1

Answer:

Answer: Molarity is 0.25 M

Explanation: Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Formula used :

Molarity=\frac{n\times 1000}{V_s}Molarity=

V

s

n×1000

where,

n= moles of solute

Moles=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}}=\frac{10}{40}=0.25molesMoles=

Molar mass of solute

Given mass of solute

=

40

10

=0.25moles

V_sV

s

= Volume of solution in ml

Now put all the given values in the formula of molarity, we get

Molarity=\frac{0.25moles\times 1000}{100ml}=2.5mole/LMolarity=

100ml

0.25moles×1000

=2.5mole/L

Therefore, the molarity of solution will be 0.25 mole/L.

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