Science, asked by bhagatdiksha345, 11 months ago

a solution is prepared by dissolving 15.0 gram of sodium chloride in 200 gram of water. what is the mass by mass percentage of sodium chloride in the solution?​

Answers

Answered by pranshuagarwal48
26

Answer:

15g made up to 200ml with water = 7.5% w/v

Explanation:

You’re looking for % w/w, so :

Total weight of solution = weight of solute + weight of solvent : (15 + 200)g = 215g

Weight of solute = 15g

So, %w/w = 15/215 = 6.976% or approx 7% w/w

If you were doing % w/v :

Assuming the addition of salt DOES NOT INCREASE SOLUTION VOLUME :

15g/200ml = 7.5% w/v

But this doesn’t hold true, as adding salt to water will increase the volume, but not by 1ml for 1g (more like 1ml for every 2g)

If you were doing this properly :

15g made up to 200ml with water = 7.5% w/v

Answered by Anonymous
28

Answer:

7%

Explanation:

Given :

  • Mass of solute = Mass of sodium chloride = 15.0 grams

  • Mass of solvent = Mass of water = 200 grams

To find :

  • Mass by mass per cent of sodium chloride

Mass by mass per cent = mass of solute/Mass of solution × 100

Mass of solution = Mass of solute + Mass of solvent

Mass of solution = 15+200 = 215 grams

Mass by mass per cent = 15/215×100

Mass by mass per cent of sodium chloride = 6.97%

The mass by mass percent of sodium chloride is approximately equal to 7%

Mass percent of water = 100%-7% = 93%

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