Question

a solution is prepared by dissolving 15 gram of sodium chloride in 200 gram 200 grams of H2O what is the mass by mass percentage of NaCl in the solution

Answer 1

Mass of solute (NaCl) = 15g
Mass of solvent (H2O) = 200g
Mass of solution = 200+ 15
= 215g
Mass percentage of NaCl= Mass of Nacl÷Mass of solution× 100
=15÷215×100
=6.97
=7% approx

Answer 2

Answer:

The mass by mass percentage of NaCl in the solution is 6.97%.

Explanation:

The mass by mass percentage of NaCl in the solution is given as,

$M=\frac{m_s}{M_s} \times 100$    (1)

Where,

M=mass percentage of NaCl in the solution

$m_s$=mass of solute

$M_s$=mass of solution

From the question we have,

Mass of sodium chloride(NaCl)=15gram

Mass of water(H₂O)=200gram

For the solution given in question NaCl is solute and H₂O is the solvent.

The mass of the solution is calculated as,

$M_s=15+200=215 gram$    (2)

By substituting the values in equation (1) we get;

$M=\frac{15}{215} \times 100$

$M=6.97\%$

Hence, the mass by mass percentage of NaCl in the solution is 6.97%.