Chemistry, asked by kashyhh, 18 days ago

A solution is prepared by dissolving 2:45g of H2SO4 in 500ml of solution. Calculate pH of th solution​

Answers

Answered by VishnuNN
0

Answer:

The pH of the given H₂SO₄ solution is 1.

Explanation:

Given,

       mass of H₂SO₄ = 2.45g

   volume of solution = 500mL = 0.5L

molar mass of H₂SO₄ = 98g/mol.

                 H₂SO₄ → 2H⁺ + SO₄²⁻

1 mole of H₂SO₄ produces 2 moles of H⁺ ion.

 moles of H₂SO₄ = mass of H₂SO₄ / molar mass of H₂SO₄

⇒                           = 2.45 / 98 = 0.025moles

molar concentration = moles of H₂SO₄  / liters of solution

⇒                                = 0.025/ .5 = 0.05M

then the concentration of H⁺ is,

              [H⁺] = 2 × 0.05 = 0.1M

pH of the solution is given by,

             pH = - log [H⁺]

⇒               = - log(0.1) = 1

Hence, the pH of the solution is 1.

     

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