Question

A solution is prepared by dissolving 2 gram of substance A in 18 gram of water. Calculate the mass percentage of solute and solvent​

Answer 1

Mass of solute = 2 grams

Mass of solvent = 18 grams

Mass of Solution = Mass of solute + Mass of solvent

=> Mass of Solution =( 2 +18) grams

=> Mass of Solution = 20 grams

$\boxed{\boxed{\tt Mass \: percentage = \frac{Mass \: of \: Solute}{Mass \: of \: Solution} \times 100 \: }}$

or

$\boxed{\boxed{\tt Mass \: percentage = \frac{Mass \: of \: Solvent}{Mass \: of \: Solution} \times 100 \: }}$

$\tt \longrightarrow Mass \: percentage \:of \: solute= \dfrac{2}{20} \times 100 \:$

$\tt \longrightarrow Mass \: percentage \: of \: solute = \dfrac{1}{1} \times 10 \: = 10 \%$

$\tt \longrightarrow Mass \: percentage \:of \: solvent= \dfrac{18}{20} \times 100$

$\tt \longrightarrow Mass \: percentage \:of \: solvent= \dfrac{9}{1} \times 10 = 90\%$

Answer :

mass percentage of solute = 10%

mass percentage of solvent = 90%