Question

A solution is prepared by dissolving 2 moles of solute in 4 liters of the solution what is the molarity of the solution
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Answer 1

ANSWER

Given conditions ⇒

Volume of the Aqueous solution = 500 mL.

No. of moles of HCl = 2 moles.

∵ Molarity = No. of moles/Volume in mL × 1000

∴ Molarity = 2/500 × 1000

= 4 M.

Hence, the molarity of the solution is 4 M.