Question

A solution is prepared by dissolving 20g of HCl
 into enough water to make 300.0mL of solution. Calculate its molarity.​

Answer 1

Given :

Mass of HCl = 20g

Volume of the solution = 300mL

To Find :

Molarity of the solution.

Solution :

• Definition : Number of moles of solute dissolved in one litre (or one dm³) of solution$.$

• Effect of temperature : Changes with change in temperature.

• Symbol : M

• Unit : Moles per litre

• Formula : M = n × 1000 / V(ml)

• n denotes moles of solute
• V(ml) denotes volume in ml

Molar mass of HCl = 36.5 g/mol

Moles of HCl = 20/36.5 = 0.55

By substituting the given values;

➙ M = n × 1000 / V(ml)

➙ M = 0.55 × 1000/300

➙ M = 5.5/3

➙ M = 1.83 moles/litre

Answer 2

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Given :

Mass of HCl = 20g

Volume of the solution = 300mL

To Find :

Molarity of the solution.

Solution :

• Definition : Number of moles of solute dissolved in one litre (or one dm³) of solution..

• Effect of temperature : Changes with change in temperature.

• Symbol : M

• Unit : Moles per litre

• Formula : M = n × 1000 / V(ml)

• n denotes moles of solute
• V(ml) denotes volume in ml

Molar mass of HCl = 36.5 g/mol

Moles of HCl = 20/36.5 = 0.55

By substituting the given values;

➙ M = n × 1000 / V(ml)

➙ M = 0.55 × 1000/300

➙ M = 5.5/3

➙ M = 1.83 moles/litre

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Hope it helps :)