Question

A solution is prepared by dissolving 20g of HCl
 into enough water to make 300.0mL of solution. Calculate its molarity.​

Answer 1

300ml ÷ 20g

= 15ml.g^-1

I think so .

if it's wrong forgive me

Answer 2

$Molarity = Moles of solute (moles)Volume of soltion (L) \\ </p><p></p><p>= 18.25⋅g36.50⋅g⋅mol−1×10.500L \\  = 1.00⋅mol⋅L−1</p><p></p><p></p><p>$

Answer 3

$Molarity = Moles of solute (moles)Volume of soltion (L) \\ </p><p></p><p>= 18.25⋅g36.50⋅g⋅mol−1×10.500L \\  = 1.00⋅mol⋅L−1</p><p></p><p></p><p>$