A solution is prepared by dissolving 394g of a non volatile solute in 622 of h20 The vapour pressure of solution is found 3074H gat 30 if vapour pressure of water 30.31.8Hg. what is the imolar mass of solute
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Explanation:
According to raoult's law,
p
0
p
0
−p
=
m×W
w×M
Where,
p
0
is Vapour pressure of pure water
p is vapour pressure of solvent
w is weight of solute
m is molecular weight of solute
W is molecular weight of solvent
32
32−31.84
=
m×200
10×18
⇒m=
0.005
0.9
=180
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