A solution is prepared by dissolving 43 g of naphthalene(128g) in 117 g of benzene(78g).Calculate the mole fraction both component.
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I have not read it that's why I can not answer
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Explanation:
Mole fraction of naphthalene
= (43÷128)÷1.835
= 0.182.
Mole fraction of benzene =
(117÷78)÷1.834 = 0.817.
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