Question

A solution is prepared by dissolving 5.64gm glucose in 60gm of water.calculate the following.
a. Mass% of each glucose and water
b.molality of the solution
c. Mole fraction of each of glucose and water

Answer 1

Answer:

(i) Total mass of solution

=5.64+60=65.64g

Mass percent of glucose =

65.64

5.64

×100=8.59%

Mass per cent of water =(100−Mass per cent of glucose)

=(100−8.59)=91.41%

(ii) No. of moles of glucose =

180

5.64

Mass of water in kg =

1000

60

Molality =

180

5.64

×

60

1000

=0.522m

(iii) No. of moles of glucose =

180

5.64

=0.0313

No. of moles of water =

18

60

=3.333

Mole fraction of glucose =

3.333+0.0313

0.0313

=0.0093

Mole fraction of water =

3.333+0.0313

3.333

=0.9907

Answer 2

Explanation:

Sulfuric acid is sometimes referred to as the “king of chemicals” because it is produced worldwide in such large quantities. In fact, per capita use of sulfuric acid has been taken as one index of the technical development of a country. Annual production in the United States, which is the world’s leading producer, is well over 39 billion kg (86 billion pounds). It is the cheapest bulk acid.