Question

A solution is prepared by mixing 100 ml of methanol, 120 ml of acetone and 270
ml of water. What is the volume percent of methanol and acetone in the solution?

Answer 1

Answer:

1. volume% of Methanol = (100×100/490)% =20%
2. volume% of acetone=(120×100/490)%=24.48%
3. volume% of Methanol and acetone =(220×100\490)% =44.89%