Question

A solution is prepared by mixing 8.5 g of ch2cl2 and 11.95 g of chcl3 complete solution

Answer 1

Answer:

Explanation:

Considering that we need to find the composition of the complete solution prepared by mixing 8.5g of CH2Cl2 and 11.95g of CHCl3

For finding the composition of the complete solution we need to find the intial number of moles of the two compounds before mixing.

Number of moles of a particular compound= Given mass of the particular compound÷Molecular mass of that compound

Molecular mass of CH2Cl2= 12+2+71

                                           =85g

Number of moles of CH2Cl2= 8.5÷85

                                             =0.1 mole of CH2Cl2

Molecular mass of CHCl3= 12+1+106.5

                                           =119.5g

mass of CHCl3 mixed = 11.95 g

Number of moles of CHCl3= 11.95÷119.5

                                            =0.1 moles

Therefore the final or the solution formed by mixing of the two components has 0.1mole of CH2Cl2 and 0.1 mole of CHCl3