A solution is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is
0.9.
a) What is the molality (m) of the solution?
b) Water is added to the above solution such that the mole fraction of water in the solution
becomes 0.9 What is the molality (m) of the solution?
Answers
Answered by
1
A solution is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is
Answered by
1
Answer:
1]
Ethanol = 0.9
Water present in mixture = 0.1
Molality = 0.9 × (12 + 3 + 12 + 2 + 16 + 1)
Molality = 0.9 × 46
Molality = 41.4 gm/1000 = 0.0414 kg
Molality = 0.1/0.414
= 2.415 m%
_________________________
2]
mole fraction of ethanol = 1 - 0.9 = 0.1
Finding mass of water
0.9 × 18 = 16.2 gm = 0.0162 kg
Molality = 0.1/0.0162 kg
= 6.173
_________________________
Thanks!!
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