Question

A solution is prepared by mixing ethanol and water. The mole fraction of ethanol in the mixture is
0.9.
a) What is the molality (m) of the solution?
b) Water is added to the above solution such that the mole fraction of water in the solution
becomes 0.9 What is the molality (m) of the solution?

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Answer 1

Answer:

What is the molality (m) of the solution? Mole fraction of ethanol is 0.9 and is greater than the mole fraction of water (i.e., 1 - 0.9 = 0.1), so ethanol is solvent and water is solute. Thus X1=0.9 and X2=0.1(Mw1=46 and Mw2=18).

Step-by-step explanation:

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Answer 2

Answer :-

1]

Ethanol = 0.9

Water present in mixture = 0.1

Molality = 0.9 × (12 + 3 + 12 + 2 + 16 + 1)

Molality = 0.9 × 46

Molality = 41.4 gm/1000 = 0.0414 kg

Molality = 0.1/0.414

= 2.415 m%

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2]

mole fraction of ethanol = 1 - 0.9 = 0.1

Finding mass of water

0.9 × 18 = 16.2 gm = 0.0162 kg

Molality = 0.1/0.0162 kg

= 6.173

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