Question

a solution is prepared by the dissolving 45 gram of a sugar in 180 gram of water calculate the mass of percentage of solute​

Answer 1

Answer:

80 %

Explanation:

45g+180g =225g

Mass% of water: (180/225)*100

=(180/15*3)*100

=(180/9)*4

= 80%

Answer 2

Answer:

Question :

A solution is prepared by dissolving 45 g ofsugar in 180 g of water. Calculate the masspercentage of solute.

Answer :

$Mass \: percentage \: \\ \\ = \frac{Mass \: of \: the \: solute}{Mass \: of \: the \: solution} \times 100\\ \\ \\ Given : \: \\ \\ Mass \: of \: solute \: = \: 45 \: grams \\ \\ Mass \: of \: solvent \: (water) = 180 \: grams \\ \\ Mass \: of \: the \: solution \: \\ \\ = Mass \: of \: solute \: + \: Mass \: of \: solvent \: \\ \\ = 180 + 45 = 225 \: grams \\ \\ Mass \: percentage \: = \frac{45}{225} \times 100 \\ \\ = 20 \:$

Therefore, the Mass percentage of solute is 20%.

Tip to do :

• Just substitute and find the value..

Thank you !