Question

A solution is to be used in hand lotion is made by mixing 90.0g of water,9.2g of ethyl alcohol and 18.4g of glycerol .calculate the mole fraction of glucerol present in it

Answer 1

the mole of each of them
let xA = moles of water
so xA = given mass /molar mass
xA= 90/18 = 5 moles

let xB =moles of ethyl alcohol
xB = 9.20/46 = 0.2 moles
and
the xC = moles of glycerol
xC = 18.4/92 = 0.2
so the mole fraction of
glycerol = xC/xA+xB+xC
= 0.2/5+0.2+0.2
= 0.037

Answer 2

Answer:

.37

Explanation:

Mole of each of them

let ×A=mole of water

so ×A= Give mass/molar mass

×A= 90/18=5mole

Let ×B = Mole of ethyl alcohol

×B = 9.20/46=.2

×C= mole of glycerol

×C= 18.4/92=.2

So the mole fraction of glycerol = ×C/×A+×B+×C

=.2/5+.2+.2

=.37