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hey there !!,
length of sqr. = 10cm
now given 2cm is height of the trapezium .
therefore side of the shaded sqr. = 10-4 = 6cm
now ,
area of shaded sqr. = 6² = 36 cm²
hope it helps ,
be brainly , together we go far !!♥
length of sqr. = 10cm
now given 2cm is height of the trapezium .
therefore side of the shaded sqr. = 10-4 = 6cm
now ,
area of shaded sqr. = 6² = 36 cm²
hope it helps ,
be brainly , together we go far !!♥
butterflyqueen:
how ?
ye naya formula nhi h
han ,,, yaar height nahi ,, base of triangle nikalne ka ye formula hota h ,,, trapeZium me
when u draw perpendicular from the vertex than triangle banegaa naa ,, uska base nikalne ka ye formula hota h
than uske baad right angle triangle banega uska height phir nikalenge phythagoras se ,,, hahahah
Answered by
8
solution:
Here, it is given that,
The trapizium are congruent to each other,
it means height is same in all trapizum.
Now, we have to subtract , "2" from both side of big square.
so, let lenght of small square be x cm
then, A/Q ,
length of small square + 2×2 = 10
=> x + 4 = 10
=> x = 6
thus, side of square = 6 cm
Now, area of square = side × side
Area = 6 cm × 6 cm = 36 cm^2
--------------------
Thus, correct option is (b)
___________
star_ing _ Amrit⭐
Here, it is given that,
The trapizium are congruent to each other,
it means height is same in all trapizum.
Now, we have to subtract , "2" from both side of big square.
so, let lenght of small square be x cm
then, A/Q ,
length of small square + 2×2 = 10
=> x + 4 = 10
=> x = 6
thus, side of square = 6 cm
Now, area of square = side × side
Area = 6 cm × 6 cm = 36 cm^2
--------------------
Thus, correct option is (b)
___________
star_ing _ Amrit⭐
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