Question

a solution obtain by mixing 300g of 25% and 400g of 40% solution by mass . calculate the mass % of solution

Answer 1

heya..........


Mass of solute (1) = 300g × 25/100 = 75 g


Mass of solute (2) = 400g ×40/100= 160g

Total mass of solute = 75+160 = 235g


Total mass of solution = 300 + 400  = 700g


% composition by mass of solute = mass of solute / total mass of solution ×100                                                      = 235/700 ×100
                                           = 33.57% of solute

% composition by mass of solvent = 100 - 33.57                                                   
                                                      = 66.43%


Hope it helps...

tysm.........#gozmit

Answer 2

$\huge\bold{\green{Answer :-}}$

Percentage of solute in the final solution = $\bold{33.5\%}$

Percentage of water in the final solution = $\bold{65.5\%}$

$\fbox{\texttt{\pink{Given\::}}}$

Amount of :

Solute 1 = $\bold{300\:g\:of\:25\%solution}$

Solute 2 = $\bold{400\:g\:of\:40\%solution}$

$\fbox{\texttt{\orange{To\:find\::}}}$

Mass percentage of the resulting solution.

$\fbox{\texttt{\red{How\:to\:Find\::}}}$

Amount of solute 1 = $\bold{\frac{300\times25}{100}=75\:g}$

Amount of solute 2 = $\bold{\frac{400\times40}{100}=160\:g}$

Now,

Total solute = $\bold{75+160=235\:g}$

Total solution = $\bold{300+400=700\:g}$

$\therefore$

Percentage of solute in the final solution =

$\bold{\frac{235}{700}\times100=33.5\%}$

Percentage of water in the final solution =

$\bold{100-33.5=65.5\%}$