A solution of 0.1 M acetic acid at 250 C has a specific conductance of 5.226 x 10-4 ohm-1 cm-1 .
i) find the equivalent conductivity of 0.1 M acetic acid.
ii) Find the equivalent conductivity of acetic acid at infinite dilution .
( Ka for acetic acid is= 1.8 x10-5 )
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Answer:
The specific conductance of a 0.01M solution of acetic acid at 298K is 1.65×10
−4
ohm
−1
cm
−1
. The molar conductance at infinite dilution for H
+
ion and CH
3
COO
−
ion are 349.1ohm
−1
cm
2
mol
−1
and 40.9ohm
−1
cm
2
mol
−1
respectively.
Calculate:
(i) Molar conductance of the solution.
(ii) Degree of dissociation of CH
3
COOH.
(iii) Dissociation constant for acetic acid.
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