Question

a solution of 12.5g urea in 170g of water gave a boiling point elevation of 0.63k calculate the molar mass of urea urea taking k =, 0.52k/m​

Answer 1

for solving this you should remember the formula that delta tb =kb *m

Answer 2

The molar mass of urea is 60 g/mol

Explanation:

Elevation in boiling point

$T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution

$T^o_b$ = boiling point of solvent

$k_b$ = boiling point constant  = $0.52K/m$

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

$w_2$ = mass of solute (urea) = 12.5 g

$w_1$ = mass of solvent (water) = 170 g

$M_2$ = molar mass of solute (urea) = ?

Now put all the given values in the above formula, we get:

$0.63K/m=1\times (0.52K/m)\times \frac{(12.5g)\times 1000}{M_2\times (170g)}$

$M_2=60g/mol$

Therefore, the molar mass of urea is 60 g/mol

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