Question

a solution of 2.5 grams of a non volatile solutedissolved in hundred grams of benzene boiled 0.42 degree centigrade higher than the boiling point of pure benzene. when the molecular mass of the substance (molal elevation constant of benzenes 2.67k kg mol^-1)

Answer 1

158.92 is a correct answer for the above question

Answer 2

hiii mate

a solution of 2.5 grams of a non volatile solutedissolved in hundred grams of benzene boiled 0.42 degree centigrade higher than the boiling point of pure benzene. when the molecular mass of the substance (molal elevation constant of benzenes 2.67k kg mol^-1)???

$answer$

Solution of non volatile solute = 2.5 grams

Dissolved at temperature

= 0.42 °C

= 2.67 × 2.5 × 10 ÷ 0.42

= 66.75 ÷ 0.42

= 158.9

Hope it helps ☺️